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0=0.057x-0.001x^2
We move all terms to the left:
0-(0.057x-0.001x^2)=0
We add all the numbers together, and all the variables
-(0.057x-0.001x^2)=0
We get rid of parentheses
0.001x^2-0.057x=0
a = 0.001; b = -0.057; c = 0;
Δ = b2-4ac
Δ = -0.0572-4·0.001·0
Δ = 0.003249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.057)-\sqrt{0.003249}}{2*0.001}=\frac{0.057-\sqrt{0.003249}}{0.002} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.057)+\sqrt{0.003249}}{2*0.001}=\frac{0.057+\sqrt{0.003249}}{0.002} $
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